0=x^2+1.80x-0.12402

Solution for 0=x^2+1.80x-0.12402 equation:

0=x^2+1.80x-0.12402

We move all terms to the left:

0-(x^2+1.80x-0.12402)=0

We add all the numbers together, and all the variables

-(x^2+1.80x-0.12402)=0

We get rid of parentheses

-x^2-1.80x+0.12402=0

We add all the numbers together, and all the variables

-1x^2-1.8x+0.12402=0

a = -1; b = -1.8; c = +0.12402;
Δ = b2-4ac
Δ = -1.82-4·(-1)·0.12402
Δ = 3.73608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.8)-\sqrt{3.73608}}{2*-1}=\frac{1.8-\sqrt{3.73608}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.8)+\sqrt{3.73608}}{2*-1}=\frac{1.8+\sqrt{3.73608}}{-2}
$